What is the integral of cos(pint) ?

The integral of cos(pint) is 1/(pin)sin(pint)+C

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integral of cos(pint)

\int cos (πn t) d t

\frac{1}{πn} sin (πn t) + C

Solution steps

\int cos (πn t) d t

Apply u-substitution

: \int \frac{cos ( u )}{πn} d u

= \int \frac{cos ( u )}{πn} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{πn} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{πn} sin (u)

Substitute back

u = πn t

= \frac{1}{πn} sin (πn t)

Add a constant to the solution

= \frac{1}{πn} sin (πn t) + C

n = 1 \sum \infty (\frac{π}{6})^{n}

(tan (x))^{\frac{3}{x}}

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = 7 + e^{\frac{x}{2}}

\int t (t^{6} + t - 5) d t

x \to \infty lim (3 e^{- 3 x})

What is the integral of cos(pint) ?
The integral of cos(pint) is 1/(pin)sin(pint)+C