What is (\partial)/(\partial x)(xye^{-9y}) ?

The answer to (\partial)/(\partial x)(xye^{-9y}) is e^{-9y}y

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(\partial)/(\partial x)(xye^{-9y})

\frac{\partial}{\partial x} (x y e^{- 9 y})

e^{- 9 y} y

Solution steps

\frac{\partial}{\partial x} (x y e^{- 9 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y e^{- 9 y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= y e^{- 9 y} \cdot 1

Simplify

= e^{- 9 y} y

\frac{a}{s}

x = y^{4}, y = - x^{5}

\int_{2}^{6} 7 x^{3} d x

f (x) = e^{x} - 3 x

\frac{\partial}{\partial y} (5 x y - 10 y)

What is (\partial)/(\partial x)(xye^{-9y}) ?
The answer to (\partial)/(\partial x)(xye^{-9y}) is e^{-9y}y