What is the tangent of y=7x-x^2(1.6) ?

The tangent of y=7x-x^2(1.6) is y=(7-3.2a_{0})x+1.6a_{0}^2

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tangent of y=7x-x^2(1.6)

tangent of

y = 7 x - x^{2} (1.6)

y = (7 - 3.2 a_{0}) x + 1.6 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0} - a_{0}^{2} \cdot 1.6)

Find the slope of

y = 7 x - x^{2} 1.6 : \frac{d y}{d x} = 7 - 3.2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7 - 3.2 a_{0}

Find the line with slope m=

7 - 3.2 a_{0}

and passing through

(a_{0}, 7 a_{0} - a_{0}^{2} 1.6) : y = (7 - 3.2 a_{0}) x + 1.6 a_{0}^{2}

y = (7 - 3.2 a_{0}) x + 1.6 a_{0}^{2}

e^{x} - 2 x

\frac{d}{d x} (\frac{2 x ^{2} + 4 x + 6}{x})

\frac{d}{d x} (4 x^{2} - 4 x + 1)

f (x) = arcsin (ln (x))

x \to 1 lim (1 - \frac{1}{3 x - 1})

What is the tangent of y=7x-x^2(1.6) ?
The tangent of y=7x-x^2(1.6) is y=(7-3.2a_{0})x+1.6a_{0}^2