What is the integral from-2 to sin(x) of 3t ?

The integral from-2 to sin(x) of 3t is 3((sin^2(x))/2-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to sin(x) of 3t

\int_{- 2}^{s i n (x)} 3 t d t

3 (\frac{sin ^{2} ( x )}{2} - 2)

Solution steps

\int_{- 2}^{s i n (x)} 3 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 2}^{s i n (x)} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{- 2}^{s i n (x)}

= 3 [\frac{t ^{2}}{2}]_{- 2}^{s i n (x)}

Compute the boundaries:

\frac{sin ^{2} ( x )}{2} - 2

= 3 (\frac{sin ^{2} ( x )}{2} - 2)

\int_{0}^{1} \frac{2}{3} (x + 2 y) d x

\frac{d}{d x} (a x + cot (a x))

y^{^{''}} + 16 y = 40 sec (4 t)

x \to - 4 + lim (\frac{- 4 x}{x + 4})

f (x) = 2 sin^{2} (x)

What is the integral from-2 to sin(x) of 3t ?
The integral from-2 to sin(x) of 3t is 3((sin^2(x))/2-2)