What is the solution for (dy)/(dx)=(2x+sec^2(x))/(2y),y(0)=-7 ?

The solution for (dy)/(dx)=(2x+sec^2(x))/(2y),y(0)=-7 is y=-sqrt(x^2+tan(x)+49)

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(dy)/(dx)=(2x+sec^2(x))/(2y),y(0)=-7

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 7

y = - x^{2} + tan (x) + 49

Solution steps

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{2 y}

Solve separable ODE:

y = - x^{2} + tan (x) + 49

y = - x^{2} + tan (x) + 49

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What is the solution for (dy)/(dx)=(2x+sec^2(x))/(2y),y(0)=-7 ?
The solution for (dy)/(dx)=(2x+sec^2(x))/(2y),y(0)=-7 is y=-sqrt(x^2+tan(x)+49)