What is the first derivative of-3x-2 ?

The first derivative of-3x-2 is -3

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derivative of-3x-2

\frac{d}{d x} (- 3 x - 2)

- 3

Solution steps

\frac{d}{d x} (- 3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= - 3 - 0

Simplify

= - 3

\int x (x + 2) d x

\int \frac{e ^{x} e ^{x} - 1}{e ^{x} + 3} d x

\frac{d y}{d x} = \frac{1}{x ^{2} + 1} - \frac{1}{1 - x ^{2}}

n = 1 \sum \infty (\frac{1}{8})^{n}

\frac{d}{d x} (\frac{x + 3}{x ^{3} + x - 2})