What is the solution for (y-2)dy+xdx=0 ?

The solution for (y-2)dy+xdx=0 is y=2+sqrt(-x^2+c_{1)+4},y=2-sqrt(-x^2+c_{1)+4}

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(y-2)dy+xdx=0

(y - 2) d y + x d x = 0

y = 2 + - x^{2} + c_{1} + 4, y = 2 - - x^{2} + c_{1} + 4

Solution steps

(y - 2) d y + x d x = 0

Solve separable ODE:

y = 2 + - x^{2} + c_{1} + 4, y = 2 - - x^{2} + c_{1} + 4

y = 2 + - x^{2} + c_{1} + 4, y = 2 - - x^{2} + c_{1} + 4

y = x + 2, y = \frac{1}{x + 1}, [0, 2]

\frac{d}{d x} (5 x^{3} + 3 x)

\frac{\partial}{\partial x} (\frac{x ^{3} + 5}{y ^{3} - 1})

\frac{d}{d x} (arccos (e^{3 x}))

\frac{1}{x ^{3}}

What is the solution for (y-2)dy+xdx=0 ?
The solution for (y-2)dy+xdx=0 is y=2+sqrt(-x^2+c_{1)+4},y=2-sqrt(-x^2+c_{1)+4}