What is the integral of 9rcos(r) ?

The integral of 9rcos(r) is 9(rsin(r)+cos(r))+C

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integral of 9rcos(r)

\int 9 r cos (r) d r

9 (r sin (r) + cos (r)) + C

Solution steps

\int 9 r cos (r) d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int r cos (r) d r

Apply Integration By Parts

: r sin (r) - \int sin (r) d r

= 9 (r sin (r) - \int sin (r) d r)

\int sin (r) d r = - cos (r)

= 9 (r sin (r) - (- cos (r)))

Simplify

= 9 (r sin (r) + cos (r))

Add a constant to the solution

= 9 (r sin (r) + cos (r)) + C

y = x^{4 x}

\frac{d y}{d x} = (y^{2} - 4)

x \to - 2 lim (x + 1)

n = 1 \sum \infty 1 \cdot (\frac{1}{5})^{n}

\int e^{x} 23 + e^{x} d x

What is the integral of 9rcos(r) ?
The integral of 9rcos(r) is 9(rsin(r)+cos(r))+C