What is the derivative of t^3-3t ?

The derivative of t^3-3t is 3t^2-3

What is the first derivative of t^3-3t ?

The first derivative of t^3-3t is 3t^2-3

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derivative of

t^{3} - 3 t

3 t^{2} - 3

Solution steps

\frac{d}{d t} (t^{3} - 3 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (3 t)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (3 t) = 3

= 3 t^{2} - 3

(4 z + e^{- z^{2}})^{3}

\int \frac{2}{e ^{2 x}} d x

\int 100 d x

\int_{0}^{2 π} sin^{2} (12 x) d x

x \to \infty lim (e^{- 3 x} cos (3 x))

What is the derivative of t^3-3t ?
The derivative of t^3-3t is 3t^2-3
What is the first derivative of t^3-3t ?
The first derivative of t^3-3t is 3t^2-3