What is the tangent of y=2x^3-2x,(-1,0) ?

The tangent of y=2x^3-2x,(-1,0) is y=4x+4

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tangent of y=2x^3-2x,(-1,0)

tangent of

y = 2 x^{3} - 2 x, (- 1, 0)

y = 4 x + 4

Solution steps

Find the slope of

y = 2 x^{3} - 2 x : \frac{d y}{d x} = 6 x^{2} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(- 1, 0) : y = 4 x + 4

y = 4 x + 4

\int x cos (x) + cos (x) - 1 d x

\int cos^{2} (x) - sin^{2} (x) d x

(t - 3)^{4}

\frac{d}{d x} (e^{2 x} + 5)

(2 x y^{2} - 7) d x + (2 x^{2} y + 5) d y = 0

What is the tangent of y=2x^3-2x,(-1,0) ?
The tangent of y=2x^3-2x,(-1,0) is y=4x+4