What is the d/(d{x)}(e^{{x}{y}}+{x}^2{z}) ?

The d/(d{x)}(e^{{x}{y}}+{x}^2{z}) is e^{{x}{y}}{y}+2{x}{z}

What is the first d/(d{x)}(e^{{x}{y}}+{x}^2{z}) ?

The first d/(d{x)}(e^{{x}{y}}+{x}^2{z}) is e^{{x}{y}}{y}+2{x}{z}

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\frac{d}{d x} (e^{x y} + x^{2} z)

e^{x y} y + 2 x z

Solution steps

\frac{d}{d x} (e^{x y} + x^{2} z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x y}) + \frac{d}{d x} (x^{2} z)

\frac{d}{d x} (e^{x y}) = e^{x y} y

\frac{d}{d x} (x^{2} z) = 2 x z

= e^{x y} y + 2 x z

\int \frac{- 3}{x ^{3}} d x

f (x) = \frac{( x + 1 ) ^{2}}{1 + x ^{2}}

\int_{1}^{4} (1 - u) u d u

\frac{3 x}{4 - x ^{2}} = y, at x = 1

\frac{d}{d x} (\frac{x ^{2} - 2 x + 3}{x + 1})

What is the d/(d{x)}(e^{{x}{y}}+{x}^2{z}) ?
The d/(d{x)}(e^{{x}{y}}+{x}^2{z}) is e^{{x}{y}}{y}+2{x}{z}
What is the first d/(d{x)}(e^{{x}{y}}+{x}^2{z}) ?
The first d/(d{x)}(e^{{x}{y}}+{x}^2{z}) is e^{{x}{y}}{y}+2{x}{z}