What is the integral of-2y+4e^{-x} ?

The integral of-2y+4e^{-x} is -2yx-4e^{-x}+C

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integral of-2y+4e^{-x}

\int - 2 y + 4 e^{- x} d x

- 2 y x - 4 e^{- x} + C

Solution steps

\int - 2 y + 4 e^{- x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 y d x + \int 4 e^{- x} d x

\int 2 y d x = 2 y x

\int 4 e^{- x} d x = - 4 e^{- x}

= - 2 y x - 4 e^{- x}

Add a constant to the solution

= - 2 y x - 4 e^{- x} + C

\int_{2}^{4} \frac{2 x - 3}{6} d x

y = \frac{7}{16 - x ^{2}}, [1, 3]

\int - sin (\frac{x}{2}) d x

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 4)

n = 1 \sum \infty 8 \cdot (0.2)^{n}

What is the integral of-2y+4e^{-x} ?
The integral of-2y+4e^{-x} is -2yx-4e^{-x}+C