What is the integral from-1 to 3 of (3x^4+5) ?

The integral from-1 to 3 of (3x^4+5) is 832/5

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integral from-1 to 3 of (3x^4+5)

\int_{- 1}^{3} (3 x^{4} + 5) d x

\frac{832}{5}

Decimal

166.4

Solution steps

\int_{- 1}^{3} 3 x^{4} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} 3 x^{4} d x + \int_{- 1}^{3} 5 d x

\int_{- 1}^{3} 3 x^{4} d x = \frac{732}{5}

\int_{- 1}^{3} 5 d x = 20

= \frac{732}{5} + 20

Simplify

\frac{732}{5} + 20 : \frac{832}{5}

= \frac{832}{5}

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What is the integral from-1 to 3 of (3x^4+5) ?
The integral from-1 to 3 of (3x^4+5) is 832/5