What is the limit as n approaches infinity of e^{-7/(sqrt(n))} ?

The limit as n approaches infinity of e^{-7/(sqrt(n))} is 1

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limit as n approaches infinity of e^{-7/(sqrt(n))}

n \to \infty lim (e^{- \frac{7}{n}})

1

Solution steps

n \to \infty lim (e^{- \frac{7}{n}})

Apply the Limit Chain Rule:

1

= 1

f (x) = 2 x^{2} e^{x} + 4 x^{3}

\int 16 - x^{2} d x

\int [v + \frac{1}{( 3 v - 1 ) ^{3}}] d v

\int 2 \cdot x \cdot y

e^{- 2 x}

What is the limit as n approaches infinity of e^{-7/(sqrt(n))} ?
The limit as n approaches infinity of e^{-7/(sqrt(n))} is 1