What is (\partial)/(\partial x)((93)/(2+x^2+y^2)) ?

The answer to (\partial)/(\partial x)((93)/(2+x^2+y^2)) is -(186x)/((2+x^2+y^2)^2)

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(\partial)/(\partial x)((93)/(2+x^2+y^2))

\frac{\partial}{\partial x} (\frac{93}{2 + x ^{2} + y ^{2}})

- \frac{186 x}{( 2 + x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{93}{2 + x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 93 \frac{\partial}{\partial x} (\frac{1}{2 + x ^{2} + y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 93 \frac{\partial}{\partial x} ((2 + x^{2} + y^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 2 + x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial x} (2 + x^{2} + y^{2})

= - \frac{1}{( 2 + x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial x} (2 + x^{2} + y^{2})

\frac{\partial}{\partial x} (2 + x^{2} + y^{2}) = 2 x

= 93 (- \frac{1}{( 2 + x ^{2} + y ^{2} ) ^{2}} \cdot 2 x)

Simplify

93 (- \frac{1}{( 2 + x ^{2} + y ^{2} ) ^{2}} \cdot 2 x) : - \frac{186 x}{( 2 + x ^{2} + y ^{2} ) ^{2}}

= - \frac{186 x}{( 2 + x ^{2} + y ^{2} ) ^{2}}

x \to 1 lim (\frac{x}{∣ x ∣})

y = (ln (x))^{l n (x)}

\frac{\partial}{\partial x} (\frac{z}{x + y})

\frac{d y}{d x} = \frac{( 2 x + 5 )}{( x ^{2} + 2 x )}, y (1) = 1

\int 2 x^{\frac{3}{2}} d x

What is (\partial)/(\partial x)((93)/(2+x^2+y^2)) ?
The answer to (\partial)/(\partial x)((93)/(2+x^2+y^2)) is -(186x)/((2+x^2+y^2)^2)