What is the d/(dt)(3t^2-30t+72) ?

The d/(dt)(3t^2-30t+72) is 6t-30

What is the first d/(dt)(3t^2-30t+72) ?

The first d/(dt)(3t^2-30t+72) is 6t-30

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\frac{d}{d t} (3 t^{2} - 30 t + 72)

6 t - 30

Solution steps

\frac{d}{d t} (3 t^{2} - 30 t + 72)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t^{2}) - \frac{d}{d t} (30 t) + \frac{d}{d t} (72)

\frac{d}{d t} (3 t^{2}) = 6 t

\frac{d}{d t} (30 t) = 30

\frac{d}{d t} (72) = 0

= 6 t - 30 + 0

Simplify

= 6 t - 30

\frac{d}{d x} (4 x e^{5 x})

\int \frac{x ^{2}}{( 5 - x ^{3} ) ^{2}} d x

\int e^{5 x} (5) d x

\int_{0}^{1} (e^{x})^{2} d x

x \to \infty lim (x^{3} - 3 x)