What is the derivative of (2x^2-1^2) ?

The derivative of (2x^2-1^2) is 8x(2x^2-1)

What is the first derivative of (2x^2-1^2) ?

The first derivative of (2x^2-1^2) is 8x(2x^2-1)

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\frac{d}{d x} ((2 x^{2} - 1)^{2})

8 x (2 x^{2} - 1)

Solution steps

\frac{d}{d x} ((2 x^{2} - 1)^{2})

Apply the chain rule:

2 (2 x^{2} - 1) \frac{d}{d x} (2 x^{2} - 1)

= 2 (2 x^{2} - 1) \frac{d}{d x} (2 x^{2} - 1)

\frac{d}{d x} (2 x^{2} - 1) = 4 x

= 2 (2 x^{2} - 1) \cdot 4 x

Simplify

= 8 x (2 x^{2} - 1)

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What is the derivative of (2x^2-1^2) ?
The derivative of (2x^2-1^2) is 8x(2x^2-1)
What is the first derivative of (2x^2-1^2) ?
The first derivative of (2x^2-1^2) is 8x(2x^2-1)