What is the derivative of f(x)=8^x ?

The derivative of f(x)=8^x is 3ln(2)*8^x

What is the first derivative of f(x)=8^x ?

The first derivative of f(x)=8^x is 3ln(2)*8^x

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derivative of

f (x) = 8^{x}

3 ln (2) \cdot 8^{x}

Solution steps

\frac{d}{d x} (8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 8^{x} ln (8)

Simplify

ln (8) : 3 ln (2)

= 3 ln (2) \cdot 8^{x}

(2 x - 3)^{3} (x^{4} + 1)^{2}

y^{^{''}} + b \cdot y = 0

\int_{1}^{2} \frac{6}{x ^{3} + 4 x} d x

x \to - 5 lim (\frac{2}{( x - 5 ) ^{3}})

y^{^{'}} + x y - 3 = 0

What is the derivative of f(x)=8^x ?
The derivative of f(x)=8^x is 3ln(2)*8^x
What is the first derivative of f(x)=8^x ?
The first derivative of f(x)=8^x is 3ln(2)*8^x