What is the derivative of f(x)=(2sqrt(x))/x ?

The derivative of f(x)=(2sqrt(x))/x is -1/(x^{3/2)}

What is the first derivative of f(x)=(2sqrt(x))/x ?

The first derivative of f(x)=(2sqrt(x))/x is -1/(x^{3/2)}

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derivative of

f (x) = \frac{2 x}{x}

- \frac{1}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{2 x}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( x ) x - \frac{d x}{d x} x}{x ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d x}{d x} = 1

= 2 \cdot \frac{\frac{1}{2 x} x - 1 \cdot x}{x ^{2}}

Simplify

2 \cdot \frac{\frac{1}{2 x} x - 1 \cdot x}{x ^{2}} : - \frac{1}{x ^{\frac{3}{2}}}

= - \frac{1}{x ^{\frac{3}{2}}}

\int 7 tan^{2} (x se) c^{3} x

\frac{\partial}{\partial x} (\frac{x y}{x + y} + z)

\frac{d}{d x} (\frac{( 2 x + 3 ) ^{4}}{( 3 x - 2 ) ^{5}})

\int_{a}^{b} arctan (x) d x

4 y^{^{'}} - (\frac{2}{x}) y = (- \frac{3}{2}) x y^{\frac{5}{2}}

What is the derivative of f(x)=(2sqrt(x))/x ?
The derivative of f(x)=(2sqrt(x))/x is -1/(x^{3/2)}
What is the first derivative of f(x)=(2sqrt(x))/x ?
The first derivative of f(x)=(2sqrt(x))/x is -1/(x^{3/2)}