What is the derivative of In(x^2+7) ?

The derivative of In(x^2+7) is 2nIx

What is the first derivative of In(x^2+7) ?

The first derivative of In(x^2+7) is 2nIx

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\frac{d}{d x} (I n (x^{2} + 7))

2 n I x

Solution steps

\frac{d}{d x} (I n (x^{2} + 7))

Treat

n, I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= I n \frac{d}{d x} (x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= I n (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (7))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7) = 0

= I n (2 x + 0)

Simplify

= 2 n I x

\int \frac{x - 3}{( x + 8 ) ( x - 2 )} d x

a^{2} - x^{2}

h (x) = \frac{2 x}{sin ( x )}

\frac{d}{d x} ((x^{2} + x) (6 - x))

\int \frac{1}{7 x + 6} d x

What is the derivative of In(x^2+7) ?
The derivative of In(x^2+7) is 2nIx
What is the first derivative of In(x^2+7) ?
The first derivative of In(x^2+7) is 2nIx