What is the limit as t approaches pi of cos(t) ?

The limit as t approaches pi of cos(t) is -1

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limit as t approaches pi of cos(t)

t \to π lim (cos (t))

- 1

Solution steps

t \to π lim (cos (t))

Plug in the value

t = π

= cos (π)

Use the following trivial identity:

cos (π) = (- 1)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - 1

(ln (sec (x)))^{^{'}}

\int 4 x + sin (3 x) d x

(6.4) (2.1)

\frac{\partial}{\partial x} (- 2 e^{- 3 x^{2} - y^{2}} y)

y = 1.00059 e^{(2.39736)} - 1.0005

What is the limit as t approaches pi of cos(t) ?
The limit as t approaches pi of cos(t) is -1