What is the derivative of 1/(2sqrt(x+7)) ?

The derivative of 1/(2sqrt(x+7)) is -1/(4(x+7)^{3/2)}

What is the first derivative of 1/(2sqrt(x+7)) ?

The first derivative of 1/(2sqrt(x+7)) is -1/(4(x+7)^{3/2)}

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\frac{d}{d x} (\frac{1}{2 x + 7})

- \frac{1}{4 ( x + 7 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x + 7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x + 7})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} ((x + 7)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 7 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 7)

= - \frac{1}{2 ( x + 7 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 7)

\frac{d}{d x} (x + 7) = 1

= \frac{1}{2} (- \frac{1}{2 ( x + 7 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

\frac{1}{2} (- \frac{1}{2 ( x + 7 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{1}{4 ( x + 7 ) ^{\frac{3}{2}}}

= - \frac{1}{4 ( x + 7 ) ^{\frac{3}{2}}}

f (x) = x \cdot e^{2 x - 4}

(9 x^{2}) (- 1 + 2 x)

\int_{0}^{2 x} sin (2 x) d x

(6 x^{2} + 8)^{6}

\int (e^{x} sin (y)) d x

What is the derivative of 1/(2sqrt(x+7)) ?
The derivative of 1/(2sqrt(x+7)) is -1/(4(x+7)^{3/2)}
What is the first derivative of 1/(2sqrt(x+7)) ?
The first derivative of 1/(2sqrt(x+7)) is -1/(4(x+7)^{3/2)}