What is the tangent of f(x)=3x^4,\at x=-2 ?

The tangent of f(x)=3x^4,\at x=-2 is y=-96x-144

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tangent of f(x)=3x^4,\at x=-2

tangent of

f (x) = 3 x^{4}, at x = - 2

y = - 96 x - 144

Solution steps

Find the tangent point:

(- 2, 48)

Find the slope of

f (x) = 3 x^{4} : \frac{df ( x )}{d x} = 12 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 96

Find the line with slope m=

- 96

and passing through

(- 2, 48) : y = - 96 x - 144

y = - 96 x - 144

\frac{8 x ^{2}}{4 - 3 x}

x^{2} - 4, - x^{2} + 4

\frac{d}{d x} ((3 x + 8) x^{2})

\int 4 csc (x) cot (x) - sec (x) tan (x) d x

y = x^{3} - 2 x + 2, (2, 6)

What is the tangent of f(x)=3x^4,\at x=-2 ?
The tangent of f(x)=3x^4,\at x=-2 is y=-96x-144