What is the derivative of (2z+e^{-z^2})^6 ?

The derivative of (2z+e^{-z^2})^6 is 6(2z+e^{-z^2})^5(2-2e^{-z^2}z)

What is the first derivative of (2z+e^{-z^2})^6 ?

The first derivative of (2z+e^{-z^2})^6 is 6(2z+e^{-z^2})^5(2-2e^{-z^2}z)

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derivative of

(2 z + e^{- z^{2}})^{6}

6 (2 z + e^{- z^{2}})^{5} (2 - 2 e^{- z^{2}} z)

Solution steps

\frac{d}{d z} ((2 z + e^{- z^{2}})^{6})

Apply the chain rule:

6 (2 z + e^{- z^{2}})^{5} \frac{d}{d z} (2 z + e^{- z^{2}})

= 6 (2 z + e^{- z^{2}})^{5} \frac{d}{d z} (2 z + e^{- z^{2}})

\frac{d}{d z} (2 z + e^{- z^{2}}) = 2 - 2 e^{- z^{2}} z

= 6 (2 z + e^{- z^{2}})^{5} (2 - 2 e^{- z^{2}} z)

f (x) = 2 - x

x \to - 4 lim (\frac{x + 8}{x + 4})

\frac{d}{d x} (\frac{x ^{2}}{5 + 6 x})

\int sin (wt) cos^{2} (wt) d t

x^{3} - 3 x + 2

What is the derivative of (2z+e^{-z^2})^6 ?
The derivative of (2z+e^{-z^2})^6 is 6(2z+e^{-z^2})^5(2-2e^{-z^2}z)
What is the first derivative of (2z+e^{-z^2})^6 ?
The first derivative of (2z+e^{-z^2})^6 is 6(2z+e^{-z^2})^5(2-2e^{-z^2}z)