What is the derivative of-ln(x-2) ?

The derivative of-ln(x-2) is -1/(x-2)

What is the first derivative of-ln(x-2) ?

The first derivative of-ln(x-2) is -1/(x-2)

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\frac{d}{d x} (- ln (x - 2))

- \frac{1}{x - 2}

Solution steps

\frac{d}{d x} (- ln (x - 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x - 2))

Apply the chain rule:

\frac{1}{x - 2} \frac{d}{d x} (x - 2)

= \frac{1}{x - 2} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= - \frac{1}{x - 2} \cdot 1

Simplify

= - \frac{1}{x - 2}

\int \frac{( x ^{2} - x + 8 )}{x ^{3} + 2 x} d x

6 t (\frac{d y}{d t}) + 5 y = t

\frac{\partial}{\partial w} (\frac{w}{h ( w ) ^{2}})

y = \frac{1}{6 x - 1}

\int_{0}^{2} (x) d x

What is the derivative of-ln(x-2) ?
The derivative of-ln(x-2) is -1/(x-2)
What is the first derivative of-ln(x-2) ?
The first derivative of-ln(x-2) is -1/(x-2)