What is the integral from 0 to 1 of 1/(x^{0.2)} ?

The integral from 0 to 1 of 1/(x^{0.2)} is 1.25

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integral from 0 to 1 of 1/(x^{0.2)}

\int_{0}^{1} \frac{1}{x ^{0.2}} d x

1.25

Solution steps

\int_{0}^{1} \frac{1}{x ^{0.2}} d x

Apply the Power Rule

: [1.25 x^{0.8}]_{0}^{1}

= [1.25 x^{0.8}]_{0}^{1}

Compute the boundaries:

1.25

= 1.25

x \to 0 - lim (x (x - 1))

\frac{d}{d x} (\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )})

\frac{\partial}{\partial x} (4 x^{3} + 2 x y^{2} + 1)

\int x^{2} arctan (4 x) d x

\frac{d}{d x} (- 15)

What is the integral from 0 to 1 of 1/(x^{0.2)} ?
The integral from 0 to 1 of 1/(x^{0.2)} is 1.25