What is the derivative of-2cos(-3x+7) ?

The derivative of-2cos(-3x+7) is -6sin(-3x+7)

What is the first derivative of-2cos(-3x+7) ?

The first derivative of-2cos(-3x+7) is -6sin(-3x+7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 2 cos (- 3 x + 7))

- 6 sin (- 3 x + 7)

Solution steps

\frac{d}{d x} (- 2 cos (- 3 x + 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (cos (- 3 x + 7))

Apply the chain rule:

- sin (- 3 x + 7) \frac{d}{d x} (- 3 x + 7)

= - sin (- 3 x + 7) \frac{d}{d x} (- 3 x + 7)

\frac{d}{d x} (- 3 x + 7) = - 3

= - 2 (- sin (- 3 x + 7) (- 3))

Simplify

= - 6 sin (- 3 x + 7)

\int e^{2 x + 7} d x

\int (2 - x)^{\frac{1}{2}} d x

x \to 5 lim (6 x - 4)

\int 3 x^{2} + 2 x + 1 d x

y^{^{''}} + y = 4 csc^{2} (t)

What is the derivative of-2cos(-3x+7) ?
The derivative of-2cos(-3x+7) is -6sin(-3x+7)
What is the first derivative of-2cos(-3x+7) ?
The first derivative of-2cos(-3x+7) is -6sin(-3x+7)