What is the solution for y^{''}-3y^'+2y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}-3y^'+2y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}-3y^'+2y=0,y(0)=0,y^'(0)=0

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) - 3 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = 0

y = 0

cos (x), \frac{π}{3}

\int \frac{3 x - 1}{x ^{2} - 1} d x

\frac{d}{d x} (\frac{9 - x ^{2}}{8 x})

n = 1 \sum \infty \frac{( x ^{n} )}{7 n}

- 2 x

What is the solution for y^{''}-3y^'+2y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}-3y^'+2y=0,y(0)=0,y^'(0)=0 is y=0