What is the solution for y^'=(y-xy)/(x^2) ?

The solution for y^'=(y-xy)/(x^2) is y=(e^{(-1+c_{1}x)/x})/(x)

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y^'=(y-xy)/(x^2)

y^{^{'}} = \frac{y - x y}{x ^{2}}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

Solution steps

y^{'} (x) = \frac{y - x y}{x ^{2}}

Solve separable ODE:

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

\int 10 sin^{6} (x) cos^{3} (x) d x

e^{5 x}

x \to o lim (\frac{sin ( 3 x )}{x})

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\frac{d}{d x} (4 x + x^{2} cos (\frac{1}{x}))

What is the solution for y^'=(y-xy)/(x^2) ?
The solution for y^'=(y-xy)/(x^2) is y=(e^{(-1+c_{1}x)/x})/(x)