What is the limit as t approaches 0 of 2/t-2/(t^2-t) ?

The limit as t approaches 0 of 2/t-2/(t^2-t) is diverges

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limit as t approaches 0 of 2/t-2/(t^2-t)

t \to 0 lim (\frac{2}{t} - \frac{2}{t ^{2} - t})

diverges

Solution steps

t \to 0 lim (\frac{2}{t} - \frac{2}{t ^{2} - t})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 0 + lim (\frac{2}{t} - \frac{2}{t ^{2} - t}) = \infty

t \to 0 - lim (\frac{2}{t} - \frac{2}{t ^{2} - t}) = - \infty

= diverges

y = sin (π - x)

\int_{4}^{8} \frac{y}{y ^{2} - 2 y - 3} d y

x^{3} - 2 x^{2} + 3, 3 x^{2} + 5 x - 22

\int - e^{6 t} d t

\frac{4}{s ( 5 s + 1 )}

What is the limit as t approaches 0 of 2/t-2/(t^2-t) ?
The limit as t approaches 0 of 2/t-2/(t^2-t) is diverges