What is the tangent of y=5x-x^2(1.4) ?

The tangent of y=5x-x^2(1.4) is y=(5-2.8a_{0})x+1.4a_{0}^2

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tangent of y=5x-x^2(1.4)

tangent of

y = 5 x - x^{2} (1.4)

y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0} - a_{0}^{2} \cdot 1.4)

Find the slope of

y = 5 x - x^{2} 1.4 : \frac{d y}{d x} = 5 - 2.8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5 - 2.8 a_{0}

Find the line with slope m=

5 - 2.8 a_{0}

and passing through

(a_{0}, 5 a_{0} - a_{0}^{2} 1.4) : y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

y = 8 x^{4}, at x = 0

f (x) = 3 + ln (x)

\frac{d}{d x} (- sin (3 x) \cdot 3)

\int \frac{x ^{3}}{x ^{2} - 4} d x

\int \frac{3 x + 1}{5 x ^{2} + 1} d x

What is the tangent of y=5x-x^2(1.4) ?
The tangent of y=5x-x^2(1.4) is y=(5-2.8a_{0})x+1.4a_{0}^2