What is the derivative of (x^2-3^4) ?

The derivative of (x^2-3^4) is 8x(x^2-3)^3

What is the first derivative of (x^2-3^4) ?

The first derivative of (x^2-3^4) is 8x(x^2-3)^3

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\frac{d}{d x} ((x^{2} - 3)^{4})

8 x (x^{2} - 3)^{3}

Solution steps

\frac{d}{d x} ((x^{2} - 3)^{4})

Apply the chain rule:

4 (x^{2} - 3)^{3} \frac{d}{d x} (x^{2} - 3)

= 4 (x^{2} - 3)^{3} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= 4 (x^{2} - 3)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} - 3)^{3}

\frac{d}{d x} ((a + \frac{b}{x ^{2}})^{3})

x y^{3}

\frac{4 2}{3} x^{\frac{3}{2}} - 1

\frac{1}{1 + x ^{2}}

\int \frac{27 x ^{2}}{x ^{2} - 4} d x

What is the derivative of (x^2-3^4) ?
The derivative of (x^2-3^4) is 8x(x^2-3)^3
What is the first derivative of (x^2-3^4) ?
The first derivative of (x^2-3^4) is 8x(x^2-3)^3