What is the derivative of In(x^2+9) ?

The derivative of In(x^2+9) is 2nIx

What is the first derivative of In(x^2+9) ?

The first derivative of In(x^2+9) is 2nIx

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\frac{d}{d x} (I n (x^{2} + 9))

2 n I x

Solution steps

\frac{d}{d x} (I n (x^{2} + 9))

Treat

n, I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= I n \frac{d}{d x} (x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= I n (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (9))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9) = 0

= I n (2 x + 0)

Simplify

= 2 n I x

\frac{d}{d x} (e^{2 x} + e^{x})

\frac{d y}{d t} = - 3 y + 12, y (0) = 6

f (x) = (4 - x^{2}) (x + 1)

\frac{d y}{d x} = \frac{1}{10} (500 y - y^{2})

\frac{d y}{d t} = e^{- y}

What is the derivative of In(x^2+9) ?
The derivative of In(x^2+9) is 2nIx
What is the first derivative of In(x^2+9) ?
The first derivative of In(x^2+9) is 2nIx