What is the derivative of ln(1-3x) ?

The derivative of ln(1-3x) is -3/(1-3x)

What is the first derivative of ln(1-3x) ?

The first derivative of ln(1-3x) is -3/(1-3x)

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derivative of

ln (1 - 3 x)

- \frac{3}{1 - 3 x}

Solution steps

\frac{d}{d x} (ln (1 - 3 x))

Apply the chain rule:

\frac{1}{1 - 3 x} \frac{d}{d x} (1 - 3 x)

= \frac{1}{1 - 3 x} \frac{d}{d x} (1 - 3 x)

\frac{d}{d x} (1 - 3 x) = - 3

= \frac{1}{1 - 3 x} (- 3)

Simplify

\frac{1}{1 - 3 x} (- 3) : - \frac{3}{1 - 3 x}

= - \frac{3}{1 - 3 x}

\int x^{2} n^{2} xx d x

\int x (3 - x) d x

\int \frac{5 e ^{x}}{e ^{2 x} + 6 e ^{x} + 9} d x

\int_{0}^{2} (4 x - x^{3}) d x

\frac{( 4 s - 3 )}{( s ^{2} + 8 s + 24 )}

What is the derivative of ln(1-3x) ?
The derivative of ln(1-3x) is -3/(1-3x)
What is the first derivative of ln(1-3x) ?
The first derivative of ln(1-3x) is -3/(1-3x)