What is the tangent of x^2+4/x-10,\at x=8 ?

The tangent of x^2+4/x-10,\at x=8 is y= 255/16 x-73

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tangent of x^2+4/x-10,\at x=8

tangent of

x^{2} + \frac{4}{x} - 10, at x = 8

y = \frac{255}{16} x - 73

Solution steps

Find the tangent point:

(8, \frac{109}{2})

Find the slope of

y = x^{2} + \frac{4}{x} - 10 : \frac{d y}{d x} = 2 x - \frac{4}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{255}{16}

Find the line with slope m=

\frac{255}{16}

and passing through

(8, \frac{109}{2}) : y = \frac{255}{16} x - 73

y = \frac{255}{16} x - 73

(- 3, 5), (- 7, - 9)

\int \frac{5 x ^{3}}{3 + x ^{2}} d x

\int x - 1 d x

y = (\frac{x - 1}{x + 1})

\frac{\partial}{\partial x} (x^{2} y + 2 x^{2} - y - 2)

What is the tangent of x^2+4/x-10,\at x=8 ?
The tangent of x^2+4/x-10,\at x=8 is y= 255/16 x-73