What is the solution for (dy)/(dt)=2(t+1)y,y(0)=1 ?

The solution for (dy)/(dt)=2(t+1)y,y(0)=1 is y=e^{t^2+2t}

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(dy)/(dt)=2(t+1)y,y(0)=1

\frac{d y}{d t} = 2 (t + 1) y, y (0) = 1

y = e^{t^{2} + 2 t}

Solution steps

\frac{d y}{d t} = 2 (t + 1) y

Solve separable ODE:

y = e^{t^{2} + 2 t}

y = e^{t^{2} + 2 t}

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What is the solution for (dy)/(dt)=2(t+1)y,y(0)=1 ?
The solution for (dy)/(dt)=2(t+1)y,y(0)=1 is y=e^{t^2+2t}