What is the derivative of (25)/(t^2)-5/t ?

The derivative of (25)/(t^2)-5/t is -(50)/(t^3)+5/(t^2)

What is the first derivative of (25)/(t^2)-5/t ?

The first derivative of (25)/(t^2)-5/t is -(50)/(t^3)+5/(t^2)

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derivative of

\frac{25}{t ^{2}} - \frac{5}{t}

- \frac{50}{t ^{3}} + \frac{5}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{25}{t ^{2}} - \frac{5}{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{25}{t ^{2}}) - \frac{d}{d t} (\frac{5}{t})

\frac{d}{d t} (\frac{25}{t ^{2}}) = - \frac{50}{t ^{3}}

\frac{d}{d t} (\frac{5}{t}) = - \frac{5}{t ^{2}}

= - \frac{50}{t ^{3}} - (- \frac{5}{t ^{2}})

Simplify

= - \frac{50}{t ^{3}} + \frac{5}{t ^{2}}

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What is the derivative of (25)/(t^2)-5/t ?
The derivative of (25)/(t^2)-5/t is -(50)/(t^3)+5/(t^2)
What is the first derivative of (25)/(t^2)-5/t ?
The first derivative of (25)/(t^2)-5/t is -(50)/(t^3)+5/(t^2)