What is area y=1+2sqrt(x),y=((3+x))/3 ?

The answer to area y=1+2sqrt(x),y=((3+x))/3 is 72

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area y=1+2sqrt(x),y=((3+x))/3

area

y = 1 + 2 x, y = \frac{( 3 + x )}{3}

72

Solution steps

Apply the area formula:

\int_{0}^{36} 1 + 2 x - \frac{1}{3} (3 + x) d x

Solve

\int_{0}^{36} 1 + 2 x - \frac{1}{3} (3 + x) d x : 72

The area is:

= 72

\frac{d}{d x} ((2 x - 3)^{4} (x^{2} + x + 1)^{5})

y^{^{''}} - 4 y = 6 e^{- x}

\int_{0}^{1} \frac{x}{x ^{2} + 1} d x

y^{4} x^{2} y^{^{'}} = 1

\frac{1}{( x + 4 ) ^{2}}

What is area y=1+2sqrt(x),y=((3+x))/3 ?
The answer to area y=1+2sqrt(x),y=((3+x))/3 is 72