What is laplacetransform f(t)=t^2-2t ?

The answer to laplacetransform f(t)=t^2-2t is 2/(s^3)-2/(s^2)

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laplacetransform f(t)=t^2-2t

laplace transform

f (t) = t^{2} - 2 t

\frac{2}{s ^{3}} - \frac{2}{s ^{2}}

Solution steps

L {t^{2} - 2 t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t^{2}} - 2 L {t}

L {t^{2}} : \frac{2}{s ^{3}}

L {t} : \frac{1}{s ^{2}}

= \frac{2}{s ^{3}} - 2 \cdot \frac{1}{s ^{2}}

Refine

\frac{2}{s ^{3}} - 2 \frac{1}{s ^{2}} : \frac{2}{s ^{3}} - \frac{2}{s ^{2}}

= \frac{2}{s ^{3}} - \frac{2}{s ^{2}}

y^{^{''''}} + 32 y^{^{''}} + 256 y = 0

\int \frac{x ^{2} - 17 x + 4}{x + 7} d x

\frac{d}{d x} (x^{2} + 4 x - 8)

x \to 0 lim (\frac{( e ^{3 x} - 1 )}{sin ( 5 x )})

\int cos^{3} (x) sin^{3} (x) d x

What is laplacetransform f(t)=t^2-2t ?
The answer to laplacetransform f(t)=t^2-2t is 2/(s^3)-2/(s^2)