What is the tangent of h(x)= 9/x ,\at x=2 ?

The tangent of h(x)= 9/x ,\at x=2 is y=-9/4 x+9

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tangent of h(x)= 9/x ,\at x=2

tangent of

h (x) = \frac{9}{x}, at x = 2

y = - \frac{9}{4} x + 9

Solution steps

Find the tangent point:

(2, \frac{9}{2})

Find the slope of

h (x) = \frac{9}{x} : \frac{d h ( x )}{d x} = - \frac{9}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{4}

Find the line with slope m=

- \frac{9}{4}

and passing through

(2, \frac{9}{2}) : y = - \frac{9}{4} x + 9

y = - \frac{9}{4} x + 9

e^{- 5 x - 3}, 5

f (x) = (x^{2} - 10 x) \cdot (x - 14)

\int 3 64 x^{5} d x

\int_{- 18}^{32} \frac{1}{∣ 2 x ∣} d x

3 - \frac{2}{s - 1}

What is the tangent of h(x)= 9/x ,\at x=2 ?
The tangent of h(x)= 9/x ,\at x=2 is y=-9/4 x+9