What is (\partial)/(\partial y)(x+2xy-3y^2) ?

The answer to (\partial)/(\partial y)(x+2xy-3y^2) is 2x-6y

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(\partial)/(\partial y)(x+2xy-3y^2)

\frac{\partial}{\partial y} (x + 2 x y - 3 y^{2})

2 x - 6 y

Solution steps

\frac{\partial}{\partial y} (x + 2 x y - 3 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (2 x y) - \frac{\partial}{\partial y} (3 y^{2})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

= 0 + 2 x - 6 y

Simplify

= 2 x - 6 y

\int_{a}^{3 a} x d x

x - 2, x, 0, 4

x \to - 7 lim (\frac{4 x + 28}{x + 7})

\int sec^{6} (x) tan^{2} (x) d x

x \to 2 lim (\frac{x ^{x} - 4}{x - 2})

What is (\partial)/(\partial y)(x+2xy-3y^2) ?
The answer to (\partial)/(\partial y)(x+2xy-3y^2) is 2x-6y