What is the integral from 0 to 1 of 1/(\sqrt[3]{x)} ?

The integral from 0 to 1 of 1/(\sqrt[3]{x)} is 3/2

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integral from 0 to 1 of 1/(\sqrt[3]{x)}

\int_{0}^{1} \frac{1}{3 x} d x

\frac{3}{2}

Decimal

1.5

Solution steps

\int_{0}^{1} \frac{1}{3 x} d x

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

\int_{0}^{25} (- 6 x) d x

x \to 2 lim (x^{3} - 5 x^{2} + 1)

\int_{0}^{2} (x + y) d y

\frac{1}{8 x}

\frac{d}{d x} (ln (e^{- 2 x} + cos (x)))

What is the integral from 0 to 1 of 1/(\sqrt[3]{x)} ?
The integral from 0 to 1 of 1/(\sqrt[3]{x)} is 3/2