What is the derivative of e^{x^2+xy} ?

The derivative of e^{x^2+xy} is e^{x^2+xy}(2x+y+x(dy)/(dx))

What is the first derivative of e^{x^2+xy} ?

The first derivative of e^{x^2+xy} is e^{x^2+xy}(2x+y+x(dy)/(dx))

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\frac{d}{d x} (e^{x^{2} + x y})

e^{x^{2} + x y} (2 x + y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (e^{x^{2} + x y})

Apply the chain rule:

e^{x^{2} + x y} \frac{d}{d x} (x^{2} + x y)

= e^{x^{2} + x y} \frac{d}{d x} (x^{2} + x y)

\frac{d}{d x} (x^{2} + x y) = 2 x + y + x \frac{d y}{d x}

= e^{x^{2} + x y} (2 x + y + x \frac{d y}{d x})

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9 x y^{^{'}} + y = 90 x

g (x) = x^{- \frac{5}{3}} - x + e^{40}

\int \frac{10}{cos ( θ ) - 1} d θ

\int x^{2} cos (\frac{n x}{2}) d x

What is the derivative of e^{x^2+xy} ?
The derivative of e^{x^2+xy} is e^{x^2+xy}(2x+y+x(dy)/(dx))
What is the first derivative of e^{x^2+xy} ?
The first derivative of e^{x^2+xy} is e^{x^2+xy}(2x+y+x(dy)/(dx))