What is area y=(25-4x^2)^2,x=-5/2 ,x= 5/2 ?

The answer to area y=(25-4x^2)^2,x=-5/2 ,x= 5/2 is 5000/3

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area y=(25-4x^2)^2,x=-5/2 ,x= 5/2

area

y = (25 - 4 x^{2})^{2}, x = - \frac{5}{2}, x = \frac{5}{2}

\frac{5000}{3}

Solution steps

Apply the area formula:

\int_{- \frac{5}{2}}^{\frac{5}{2}} 25 - 4 x^{2}^{2} d x

Solve

\int_{- \frac{5}{2}}^{\frac{5}{2}} 25 - 4 x^{2}^{2} d x : \frac{5000}{3}

The area is:

= \frac{5000}{3}

\int \frac{5 x + 3}{x ^{2} + 1} d x

n = 1 \sum \infty 1 9^{n} x^{n} n!

x \to - 2 + lim (\frac{- 6 x}{x + 2})

\int \frac{x}{x ^{4} + 2 x ^{2} + 1} d x

\frac{\partial}{\partial x} (ln (x^{4} + y^{4}) - z)

What is area y=(25-4x^2)^2,x=-5/2 ,x= 5/2 ?
The answer to area y=(25-4x^2)^2,x=-5/2 ,x= 5/2 is 5000/3