What is the derivative of (e^x/(8x^2+7)) ?

The derivative of (e^x/(8x^2+7)) is (e^x(8x^2+7)-16xe^x)/((8x^2+7)^2)

What is the first derivative of (e^x/(8x^2+7)) ?

The first derivative of (e^x/(8x^2+7)) is (e^x(8x^2+7)-16xe^x)/((8x^2+7)^2)

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\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2} + 7})

\frac{e ^{x} ( 8 x ^{2} + 7 ) - 16 x e ^{x}}{( 8 x ^{2} + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2} + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( 8 x ^{2} + 7 ) - \frac{d}{d x} ( 8 x ^{2} + 7 ) e ^{x}}{( 8 x ^{2} + 7 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (8 x^{2} + 7) = 16 x

= \frac{e ^{x} ( 8 x ^{2} + 7 ) - 16 x e ^{x}}{( 8 x ^{2} + 7 ) ^{2}}

f (x) = x (\frac{1}{x})

\int 15 d x

\frac{d}{d x} (4 x^{3} + 6 x^{2} - 5)

\frac{\partial}{\partial x} (x^{4} - 4 x^{3} y + 6 x^{2} y^{2})

- 3 x^{2} - 2 x y + 3 y^{3} = 57, (- 4, 3)

What is the derivative of (e^x/(8x^2+7)) ?
The derivative of (e^x/(8x^2+7)) is (e^x(8x^2+7)-16xe^x)/((8x^2+7)^2)
What is the first derivative of (e^x/(8x^2+7)) ?
The first derivative of (e^x/(8x^2+7)) is (e^x(8x^2+7)-16xe^x)/((8x^2+7)^2)