What is the solution for ydy=x+1dx ?

The solution for ydy=x+1dx is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ydy=x+1dx

y d y = x + 1 d x

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

Solution steps

y d y = x + 1 d x

Solve separable ODE:

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

\int \frac{1}{1 - sin ( \frac{1}{2} x )} d x

t^{2} y^{^{''}} + t y^{^{'}} + 4 y = 0

\frac{d}{d x} (x^{3} + x^{2} y + 4 y^{2}) = 6

\int 3 x^{3} cos (5 x) d x

x \to 5 lim (x^{2} + 11)

What is the solution for ydy=x+1dx ?
The solution for ydy=x+1dx is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}