What is the integral from pi/2 to pi of 5sin(x) ?

The integral from pi/2 to pi of 5sin(x) is 5

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integral from pi/2 to pi of 5sin(x)

\int_{\frac{π}{2}}^{π} 5 sin (x) d x

5

Solution steps

\int_{\frac{π}{2}}^{π} 5 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{\frac{π}{2}}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 5 [- cos (x)]_{\frac{π}{2}}^{π}

Compute the boundaries:

1

= 5 \cdot 1

Simplify

= 5

(2 y)^{^{'}}

\int \frac{1}{( x ^{2} + 1 ) ( x ^{2} + 4 )} d x

\int \frac{x}{8 x - 7} d x

\frac{\partial}{\partial z} (6 x^{\frac{y}{z}})

What is the integral from pi/2 to pi of 5sin(x) ?
The integral from pi/2 to pi of 5sin(x) is 5