What is (\partial}{\partial s}(\frac{(2r+s))/t) ?

The answer to (\partial}{\partial s}(\frac{(2r+s))/t) is 1/t

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(\partial}{\partial s}(\frac{(2r+s))/t)

\frac{\partial}{\partial s} (\frac{( 2 r + s )}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{( 2 r + s )}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (2 r + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (2 r) + \frac{\partial}{\partial s} (s))

\frac{\partial}{\partial s} (2 r) = 0

\frac{\partial}{\partial s} (s) = 1

= \frac{1}{t} (0 + 1)

Simplify

= \frac{1}{t}

\frac{d}{d y} (x sin (x y))

x \to 1 lim (\frac{1}{x - 2})

\frac{\partial}{\partial x} (3 y sin (7 y^{2} x))

\frac{2 x + 8 x ^{2}}{( 1 + 8 x ) ^{2}}

\int_{0}^{\frac{1}{3}} \frac{4}{1 + 9 x ^{2}} d x

What is (\partial}{\partial s}(\frac{(2r+s))/t) ?
The answer to (\partial}{\partial s}(\frac{(2r+s))/t) is 1/t