What is the derivative of y=(2x+e^{-x^2})^3 ?

The derivative of y=(2x+e^{-x^2})^3 is 3(2x+e^{-x^2})^2(2-2e^{-x^2}x)

What is the first derivative of y=(2x+e^{-x^2})^3 ?

The first derivative of y=(2x+e^{-x^2})^3 is 3(2x+e^{-x^2})^2(2-2e^{-x^2}x)

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derivative of

y = (2 x + e^{- x^{2}})^{3}

3 (2 x + e^{- x^{2}})^{2} (2 - 2 e^{- x^{2}} x)

Solution steps

\frac{d}{d x} ((2 x + e^{- x^{2}})^{3})

Apply the chain rule:

3 (2 x + e^{- x^{2}})^{2} \frac{d}{d x} (2 x + e^{- x^{2}})

= 3 (2 x + e^{- x^{2}})^{2} \frac{d}{d x} (2 x + e^{- x^{2}})

\frac{d}{d x} (2 x + e^{- x^{2}}) = 2 - 2 e^{- x^{2}} x

= 3 (2 x + e^{- x^{2}})^{2} (2 - 2 e^{- x^{2}} x)

\frac{d P}{d t} = P (a - b P)

y = 2 x, y = 2 x^{2} - 4

\frac{d}{d x} (∣ 2 x + 1 ∣)

\int_{1}^{8} \frac{2}{x ^{3}} d x

What is the derivative of y=(2x+e^{-x^2})^3 ?
The derivative of y=(2x+e^{-x^2})^3 is 3(2x+e^{-x^2})^2(2-2e^{-x^2}x)
What is the first derivative of y=(2x+e^{-x^2})^3 ?
The first derivative of y=(2x+e^{-x^2})^3 is 3(2x+e^{-x^2})^2(2-2e^{-x^2}x)