What is the tangent of f(x)=(2+5x)(5-4x),\at x=1 ?

The tangent of f(x)=(2+5x)(5-4x),\at x=1 is y=-23x+30

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tangent of f(x)=(2+5x)(5-4x),\at x=1

tangent of

f (x) = (2 + 5 x) (5 - 4 x), at x = 1

y = - 23 x + 30

Solution steps

Find the tangent point:

(1, 7)

Find the slope of

f (x) = (2 + 5 x) (5 - 4 x) : \frac{df ( x )}{d x} = - 40 x + 17

Compute the slope of

f (x) = (2 + 5 x) (5 - 4 x)

x = 1 : m = - 23

Find the line with slope m=

- 23

and passing through

(1, 7) : y = - 23 x + 30

y = - 23 x + 30

y^{^{'}} - y = 5.2

\int sin (3 z) cos (2) (3 z) d z

f (t) = t cos (2 t) e^{- t}, at t = 3

(1 + x^{2} + y^{2} + x^{2} y^{2}) d y = y^{2} d x

\int \frac{1}{3 x - 2} d x

What is the tangent of f(x)=(2+5x)(5-4x),\at x=1 ?
The tangent of f(x)=(2+5x)(5-4x),\at x=1 is y=-23x+30